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文章目录
  1. 题目介绍
  2. 复杂度
  3. 解题思路

Invert Binary Tree

题目介绍

LeetCode 226. Invert Binary Tree

复杂度

时间复杂度: O(n), 空间复杂度: O(n)

解题思路

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public class TreeNode {
public var val: Int
public var left: TreeNode?
public var right: TreeNode?
public init(_ val: Int) {
self.val = val
self.left = nil
self.right = nil
}
}

class Solution {
func invertTree(_ root: TreeNode?) -> TreeNode? {
guard let root = root else {
return nil
}
let temp = root.right
root.right = invertTree(root.left)
root.left = invertTree(temp)
return root
}
}
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